$ ask("本月订单最多的城市")
SELECT city, COUNT(*) AS orders
FROM orders
WHERE created_at >= '2026-10-01'
GROUP BY city
ORDER BY orders DESC;
✓ result ready01 / PROJECTS
正在进行的项目
02 / JOURNAL
abigmelon的思考
正在读取文章索引…
01 / PROJECTS
$ ask("本月订单最多的城市")
SELECT city, COUNT(*) AS orders
FROM orders
WHERE created_at >= '2026-10-01'
GROUP BY city
ORDER BY orders DESC;
✓ result ready02 / JOURNAL
正在读取文章索引…